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Question
primary 6 | Maths
| Measurement
One Answer Below
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Pls help me thx
Date Posted: 2 years ago
Views: 432
small
width - a
length - b
height - c
volume = a×b×c = 1u
big
width - 3a
length - 3b
height - 3c
volume = 3a×3b×3c = 3³ u = 9u
1u → 20
9u → 180
width - a
length - b
height - c
volume = a×b×c = 1u
big
width - 3a
length - 3b
height - 3c
volume = 3a×3b×3c = 3³ u = 9u
1u → 20
9u → 180
See 1 Answer
small
width - a
length - b
height - c
volume = a×b×c = 1u
big
width - 3a
length - 3b
height - 3c
volume = 3a×3b×3c = 3³ u = 9u
1u → 20
9u → 180
width - a
length - b
height - c
volume = a×b×c = 1u
big
width - 3a
length - 3b
height - 3c
volume = 3a×3b×3c = 3³ u = 9u
1u → 20
9u → 180
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