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secondary 4 | A Maths
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Date Posted: 2 years ago
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In part (i), recall that acceleration a = dv/dt.
In part (ii), divide the difference in velocity by the acceleration to find the time taken.
In part (iii), recall that distance s is the result of the integration of v. Using the result, substitute your answer from part (ii) to find s.
In part (iv), you just need to multiply the velocities of the vehicles by 2 seconds.
In part (v), calculate the distance travelled by the bus during the time it took for the car to decelerate to the bus' speed. Account for the distance travelled by the car as well, and see if the result is greater than the minimum distance.
In part (ii), divide the difference in velocity by the acceleration to find the time taken.
In part (iii), recall that distance s is the result of the integration of v. Using the result, substitute your answer from part (ii) to find s.
In part (iv), you just need to multiply the velocities of the vehicles by 2 seconds.
In part (v), calculate the distance travelled by the bus during the time it took for the car to decelerate to the bus' speed. Account for the distance travelled by the car as well, and see if the result is greater than the minimum distance.
Date Posted:
2 years ago
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