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primary 6 | Maths
| Measurement
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Date Posted: 2 years ago
Views: 330
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a) since both Harry and William have same amt of juice,
25 bottles + 5.8L = 37 bottles - 5.36L
37 bottles - 25 bottles = 5.8L + 5.36L
12 bottles = 11.16 L
1 bottle = 11.16L / 12 = 0.93L / bottle (ans)
b)
amt of juice Harry have =
0.93L x 25 bottles + 5.8L = 29.05L
amt of juice both of them have tgt
= 29.05L x 2 = 58.1L (ans)
25 bottles + 5.8L = 37 bottles - 5.36L
37 bottles - 25 bottles = 5.8L + 5.36L
12 bottles = 11.16 L
1 bottle = 11.16L / 12 = 0.93L / bottle (ans)
b)
amt of juice Harry have =
0.93L x 25 bottles + 5.8L = 29.05L
amt of juice both of them have tgt
= 29.05L x 2 = 58.1L (ans)
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