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secondary 4 | A Maths
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need help for part iv and clear explanation thanks
Date Posted: 2 years ago
Views: 490
Generally the solution is where the line y=k cuts the sine curve.
In this particular case there are 4 points of intersections for a
However the number of points of intersections depends on the domain (x) and b in the equation (since the sine curve repeats for every period). Are there additional information given in the earlier parts of the question?
In this particular case there are 4 points of intersections for a
However the number of points of intersections depends on the domain (x) and b in the equation (since the sine curve repeats for every period). Are there additional information given in the earlier parts of the question?
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done
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clear
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Date Posted:
2 years ago
hi sorry i still don’t understand why k more than or equals to 4 shouldn’t it be 6 since the max point is 6
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