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Question
secondary 2 | Maths
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Date Posted: 2 years ago
Views: 327
i got an answer but I’m not sure if it’s correct ima not lost
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thx
done
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clear
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Since the denominator cannot be factorized, you need to simplify it such that it can cancel out with either (a+3b) or (a-3b).
To do this, look at the 2a² at the denominator. To convert the 2a² to a, just divide it by 2a.
To obtain the 3b, do reverse multiplication (3b x 2a) = 6ab. Therefore, since the original question was -ab, you need to + 5ab to balance the equation.
Do the same thing for the -15b² and the 5ab.
To do this, look at the 2a² at the denominator. To convert the 2a² to a, just divide it by 2a.
To obtain the 3b, do reverse multiplication (3b x 2a) = 6ab. Therefore, since the original question was -ab, you need to + 5ab to balance the equation.
Do the same thing for the -15b² and the 5ab.
Date Posted:
2 years ago
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