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primary 6 | Maths
| Speed
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Hi is there any way to do this without the inverse ratio method thanks :)
Date Posted: 2 years ago
Views: 256
a)1036
b) 40km/h
I use SPEED = DISTANCE/TIME
Speed
Car : lorry = 5 : 4
When they met at middle, mean the distance travelled is the same.
Lorry, distance traveled = 4u×3 = 12u
Car, distance= 12u
Time = 12u ÷ 5u = 2.4h = 2hour 24mins
So, Car start time
= 1300-2h24m
= 1036 hr
b) Distance traveled = 240/2 = 120km
12u → 120
1u → 10
Speed = 4u = 4×10 = 40km/h
b) 40km/h
I use SPEED = DISTANCE/TIME
Speed
Car : lorry = 5 : 4
When they met at middle, mean the distance travelled is the same.
Lorry, distance traveled = 4u×3 = 12u
Car, distance= 12u
Time = 12u ÷ 5u = 2.4h = 2hour 24mins
So, Car start time
= 1300-2h24m
= 1036 hr
b) Distance traveled = 240/2 = 120km
12u → 120
1u → 10
Speed = 4u = 4×10 = 40km/h
See 1 Answer
Speed
Car : lorry = 5 : 4
When they met at middle, mean the distance travelled is the same.
Lorry, distance traveled = 4u×3 = 12u
Car, distance= 12u
Time = 12u ÷ 5u = 2.4h = 2hour 24mins
So, Car start time
= 1300-2h24m
= 1036 hr
b) Distance traveled = 240/2 = 120km
12u → 120
1u → 10
Speed = 4u = 4×10 = 40km/h
Car : lorry = 5 : 4
When they met at middle, mean the distance travelled is the same.
Lorry, distance traveled = 4u×3 = 12u
Car, distance= 12u
Time = 12u ÷ 5u = 2.4h = 2hour 24mins
So, Car start time
= 1300-2h24m
= 1036 hr
b) Distance traveled = 240/2 = 120km
12u → 120
1u → 10
Speed = 4u = 4×10 = 40km/h
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