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secondary 3 | E Maths
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I came across this question while practicing math. Im unsure on how and where to start. It would mean a lot to me id somebody could help. Thank you.
Date Posted: 2 years ago
Views: 159
Let number of chips = x and
Number of chocolates= y
x + y = 30
y = 30 - x → ①
Amount
3x + 2.5y ≤ 85 → ②
Substitute ① into ②
3x + 2.5(30-x) ≤ 85
3x + 75 - 2.5x ≤ 85
0.5x ≤ 10
x ≤ 20
Maximum number of chips that she can buy is 20
Number of chocolates= y
x + y = 30
y = 30 - x → ①
Amount
3x + 2.5y ≤ 85 → ②
Substitute ① into ②
3x + 2.5(30-x) ≤ 85
3x + 75 - 2.5x ≤ 85
0.5x ≤ 10
x ≤ 20
Maximum number of chips that she can buy is 20
Thank you!
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Hope this helps
Date Posted:
2 years ago
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