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secondary 3 | A Maths
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Hi need help with part (ii) thanks
Date Posted: 2 years ago
Views: 529
f(x) = 2(x + 1)(x^2 - 4x + 2) = 0
Consider x^2 - 4x + 2 = 0
Discriminant = (-4)^2 - 4(1)(2) = 8 > 0
x^2 - 4x + 2 = 0 has 2 distinct real roots
Hence f(x) = 0 has 3 real roots.
Consider x^2 - 4x + 2 = 0
Discriminant = (-4)^2 - 4(1)(2) = 8 > 0
x^2 - 4x + 2 = 0 has 2 distinct real roots
Hence f(x) = 0 has 3 real roots.
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Hope you understand. And highest degree of power will determine the total number of roots, which in this case is 3. The rest of the work is to determine how many are REAL roots.
Date Posted:
2 years ago
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