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secondary 2 | Maths
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Date Posted: 2 years ago
Views: 207
6 + x - 2x² = (3+2x)∙(2-x)
times - "13∙(3+2x)∙(2-x)" at both sides of equation
13×7 - 13∙(3+2x) = 2∙(6 + x - 2x²)
x² - 7x + 10 = 0
(x-2)∙(x-5) = 0
x = 5 (Ans)
times - "13∙(3+2x)∙(2-x)" at both sides of equation
13×7 - 13∙(3+2x) = 2∙(6 + x - 2x²)
x² - 7x + 10 = 0
(x-2)∙(x-5) = 0
x = 5 (Ans)
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Date Posted:
2 years ago
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Date Posted:
2 years ago
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