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secondary 3 | A Maths
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Date Posted: 2 years ago
Views: 408
8 is a factor of 56.
But 2 and 4 are factors of 8.
It follows that 2 and 4 are also factors of 56. Correct?
We use a similar idea here.
x^2 - 2x - 3 = (x - 3) (x + 1)
Both (x - 3) and (x + 1) are factors of that expression.
From there, we let both f(3) and f(-1) equal zero since there is no resultant remainder in each case.
We solve the two equations simultaneously afterwards.
But 2 and 4 are factors of 8.
It follows that 2 and 4 are also factors of 56. Correct?
We use a similar idea here.
x^2 - 2x - 3 = (x - 3) (x + 1)
Both (x - 3) and (x + 1) are factors of that expression.
From there, we let both f(3) and f(-1) equal zero since there is no resultant remainder in each case.
We solve the two equations simultaneously afterwards.
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Date Posted:
2 years ago
Thank you very much
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