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secondary 3 | E Maths
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Hi I’ve found (a) but i don’t know how to do (b) and (c)...please help me..thank you so much in advance :D
Date Posted: 2 years ago
Views: 471
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We can sketch the graph to help us understand better. “y=-3” is a horizontal line.
This means that the y-coordinate of C is already given, which is y=-3.
To find the x-coordinate of C, we substitute y=-3 into the equation of L found in (a).
This means that the y-coordinate of C is already given, which is y=-3.
To find the x-coordinate of C, we substitute y=-3 into the equation of L found in (a).
Date Posted:
2 years ago
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This is one way to solve (c). Another way is to use the linear equation (y=mx+c) and substitute the values of “m”, “x” and “y” to find “c”, where m=-1 and “x” and “y” are the x-coordinate and y-coordinate of B.
Date Posted:
2 years ago
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