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secondary 4 | A Maths
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Date Posted: 3 years ago
Views: 386
both are correct ...
using identity (sinx)^2+(cosx)^2=1
-((cosx)^2)/2+c1
= -(1-(sinx)^2)/2+c1
= ((sinx)^2)/2-1/2+c1
= ((sinx)^2)/2+c2 , where c2 = c1-1/2
therefore, the 2 expressions are equivalent.
note that the 2 'c's in the 2 expressions in the question do not represent the same constant.
using identity (sinx)^2+(cosx)^2=1
-((cosx)^2)/2+c1
= -(1-(sinx)^2)/2+c1
= ((sinx)^2)/2-1/2+c1
= ((sinx)^2)/2+c2 , where c2 = c1-1/2
therefore, the 2 expressions are equivalent.
note that the 2 'c's in the 2 expressions in the question do not represent the same constant.
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done
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Both students are correct.
Author of several O-level Science guide books (my profile pic). My forte is tutoring O-level sciences (Chemistry, Physics, Biology). Telegram Messenger: @ChillXsg Note that only my tuition students have the privilege to direct message questions, to clarify.
Author of several O-level Science guide books (my profile pic). My forte is tutoring O-level sciences (Chemistry, Physics, Biology). Telegram Messenger: @ChillXsg Note that only my tuition students have the privilege to direct message questions, to clarify.
Date Posted:
3 years ago
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