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secondary 3 | A Maths
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Damsieee
Damsieee

secondary 3 chevron_right A Maths chevron_right Singapore

Solved a) but idk how to solve with the HENCE for b).

Date Posted: 2 years ago
Views: 145

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Your answers in (a) are correct.

For (b), we notice that if we change “x” in (a) to “x/2”, we would end up with the equation in (b).

For instance, the 1st term is (a) is 2x³. If we substitute “x” with “x/2”, we get:
2(x/2)³ = 2(x³/2³) = 2x³/8 = 1/4 x³
(Not sure if you know what I mean coz I didn’t write it out but only typed it out.)

The same goes to the 2nd term and 3rd term. That’s also why the 4th term remains unchanged, since it’s just a constant without any “x”.

Hence, the solution to the new equation in (b) would be similar to (a), except that we also need to change “x” in the final step to “x/2”.

Therefore,
x/2 = -2, 1/2, 3

Multiply both sides by 2 (Take note that all 3 answers must times 2):
x = -4, 1, 6
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Wong YX
Wong Yx's answer
28 answers (A Helpful Person)
1st
Damsieee
Damsieee
2 years ago
Sounds weird but i sorta understand what you’re explaining but idk how to write it out esp with the word HENCE. like what do i even start writing? Sry for the trouble and also thx for spending ur time typing all that :)
Wong YX
Wong YX
2 years ago
No prob. The word “hence” means that you need to use the answer in (a) to solve (b) and not starting from scratch again.

I think you meant how to present your solution? I’ll take a photo of the working and post it again.
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Wong YX
Wong Yx's answer
28 answers (A Helpful Person)
The presentation of solution.
Damsieee
Damsieee
2 years ago
Ohhhhh icic. I understand now. Tysm!!!
Wong YX
Wong YX
2 years ago
No prob. I just noticed that I forgot to write “=0” behind “+6” (before the “…”).

This is just one way to present the solution. Your school teacher may have another way to present it.
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Wong YX
Wong Yx's answer
28 answers (A Helpful Person)
This is another way to present the working, but personally I find it harder to understand.