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secondary 4 | A Maths
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hi possible to help me with qs 16?? thanks topic on differentiation of triogonometric functions
Date Posted: 2 years ago
Views: 438
To prove that the stationary value is a maximum, we can take the second derivative test as follows.
dS/dθ = 64 (cos²θ - sin²θ - sin θ)
dS/dθ = 64 (cos 2θ - sin θ)
d²S/dθ²
= 64 (-2 sin 2θ - cos θ)
= 64 (-2 sin 2pi/6 - cos pi/6)
which is going to be a negative value, thus proving that the stationary value is a maximum.
dS/dθ = 64 (cos²θ - sin²θ - sin θ)
dS/dθ = 64 (cos 2θ - sin θ)
d²S/dθ²
= 64 (-2 sin 2θ - cos θ)
= 64 (-2 sin 2pi/6 - cos pi/6)
which is going to be a negative value, thus proving that the stationary value is a maximum.
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done
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To prove that the result is maximum, we can use the first derivative test or the second derivative test, but I won’t include them here.
Date Posted:
2 years ago
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