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primary 6 | Maths
| Fractions
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Hi! Help needed. Thank you
Date Posted: 2 years ago
Views: 168
Common multiple for 5 and 11 = 55
Serene = 55u + 55
Ivy = 55u
Serene gave away 7/11, so left 4/11
= 4/11×55u + 4/11×55
= 20u + 20
Ivy gave away 3/5, so left 2/5
= 2/5× 55u
= 22u
Total left
= 20u + 20 + 22u
= 44u + 20
44u+20 = 188
44u = 168
1u = 4
Total at 1st
= 55u + 55 + 55u
= 110u + 55
= 110×4 + 55
= 440 + 55
= 495
Hope this helps
Serene = 55u + 55
Ivy = 55u
Serene gave away 7/11, so left 4/11
= 4/11×55u + 4/11×55
= 20u + 20
Ivy gave away 3/5, so left 2/5
= 2/5× 55u
= 22u
Total left
= 20u + 20 + 22u
= 44u + 20
44u+20 = 188
44u = 168
1u = 4
Total at 1st
= 55u + 55 + 55u
= 110u + 55
= 110×4 + 55
= 440 + 55
= 495
Hope this helps
Thank you for the detailed solution.
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