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For your reference...
Date Posted:
7 years ago
Whr do u get -2sin? I cant get it :(
Pls helpnme :(
Differentiate cos you get negative sin.
Differentiate its angle of 2x, you get 2.
Therefore, the result of d/dx (cos 2x) = -2sin 2x.
Differentiate its angle of 2x, you get 2.
Therefore, the result of d/dx (cos 2x) = -2sin 2x.
I dont get it ? If we differentiate 2x we will get 2 only ? Why it become -2sin
Can u help me with Q c for my new question ?
I dont understand the angle part
You need to diff two times for cos (2x)... Let me write down...
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For your info...
BTW, I don't see your new question c...
BTW, I don't see your new question c...
Date Posted:
7 years ago
Wait u said must differentiate 2 times without trigo . I did that but i only get 0 if i differentiate 2x twice . And if i were to differentiate it once i will get 2 . But why is there still 2x in the eq?
Im sorry :( if i mske things complicated
The new question i posted . Abt differentiation too but part c
I don't see you new question, maybe someone else has answered it. If you need my help, pls add photo to this question so that I can see..
Do you understand my newly posted explanation on diff? Two times or not, it depends, sometimes three times!
I usually explain to my students in this way: differentiate the OUTSIDE, then the INSIDE, then the inner most INSIDE...
I usually explain to my students in this way: differentiate the OUTSIDE, then the INSIDE, then the inner most INSIDE...
Difficult to explain on paper... Are you able to approach your school teacher to clarify? If you still do not understand what I said...
I will post my new Q here in the comments sect . My teacher teach me do layer by layer. Sometimes idk how much layer ir have so its complicated :(
OK, I follow your teacher method to teach you, "layer by layer". I used "two times, three times"