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secondary 2 | Maths
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hi! can anyone help with these 2 qns please? appreciate the help!! thank youu :))
Tea = $y
2x + 4y = 4.50→①
6x + 5y = 8.60→②
Multiply 3 throughout equation ①
6x + 12y = 13.50 →③
③-②; 7y = 4.90,
y = $0.70
Substitute y=0.70 to ①,
2x + 4(0.70) = 4.50
2x = 4.50 - 2.80
x = 1.70÷2
x = $0.85
A cup of tea = $0.85
A cup of coffee = $0.70
Horses = y (4 legs)
Equation:
x + y = 71
2x + 4y = 180
x + y = 71 →①
2x + 4y = 180→②
Multiply 2 throughout equation ① ;
2x + 2y = 142→③
②-③; 2y = 38
y = 19
Substitute y = 19 to equation ①;
x + 19 =71
x = 52
Ducks = 52
Horses = 19
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