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Question
primary 5 | Maths
| Fractions
One Answer Below
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Date Posted: 2 years ago
Views: 328
Work backward...
Caili gave ¼ to Amos
Caili left ¾ (=3u)
Amos received ¼ (=1u)
Before received =2u
So, Amos gave 5/9 to Caili, he left
4/9 = 2u
2/9 = 1u
9/9 = 4.5u (Amos have at 1st)
5/9 = 2.5u
Therefore Caili at 1st have
4u - 2.5u =1.5u
Total Amos + Caili
= 4.5u + 1.5u
= 6u
Fraction Amos at 1st
= 4.5u/6u
= 45/60
= 3/4
Caili gave ¼ to Amos
Caili left ¾ (=3u)
Amos received ¼ (=1u)
Before received =2u
So, Amos gave 5/9 to Caili, he left
4/9 = 2u
2/9 = 1u
9/9 = 4.5u (Amos have at 1st)
5/9 = 2.5u
Therefore Caili at 1st have
4u - 2.5u =1.5u
Total Amos + Caili
= 4.5u + 1.5u
= 6u
Fraction Amos at 1st
= 4.5u/6u
= 45/60
= 3/4
See 1 Answer
done
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Hope this helps
Date Posted:
2 years ago
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