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secondary 4 | A Maths
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How to present using chain rule?
Circle B has a radius of 1 unit while circle C has a radius of 2 units.
So, circle C makes twice as many revolutions as circle B when referenced to circle B (i.e. with respect to circle B).
This means that y/u = 2 (i.e. y is twice of u), or dy/du = 2.
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Similarly, we compare circles A and B.
Circle A has a radius of 3 units while circle B has a radius of 1 unit.
So, circle B makes1/3 times as many revolutions as circle A when referenced to circle A (i.e. with respect to circle A).
This means that u/x = 1/3 (i.e. u is 1/3 of x), or du/dx = 2.
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The system is connected by the common circle B. So, we can say that circle C makes 2/3 as many revolutions as circle A (because when circle B makes 1 revolution, circles C and A make 2 and 3 revolutions respectively).
This means that y/x = 2/3 (i.e. y is 2/3 of x), or dy/dx = 2/3.
This can be seen by the Chain Rule
2/3 = (2) (1/3)
dy/dx = (dy/du) (du/dx)
dy/dx means how many revolutions circle C makes when circle A rotates 1 round.
dy/du means how many revolutions circle C makes when circle B rotates 1 round.
du/dx means how many recolutions circle B makes when circle A rotates 1 round.
= dy/du x du/dx
= 2 x 1/3
(as explained previously - circle C makes twice as many revolutions as circle B which in turn makes 1/3 as many revolutions as circle A)
= 2/3
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