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primary 6 | Maths | Data Analysis
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Wincy
Wincy

primary 6 chevron_right Maths chevron_right Data analysis chevron_right Singapore

Kindly help solve this question please.

Date Posted: 2 years ago
Views: 265
AC Lim
AC Lim
2 years ago
This is duck remain unchanged question.
So we made duck to same unit, 6u

Case 1,
2 chickens + 3 ducks left 50 chickens
(Made duck to 6u) by multiply 2u
4u chickens + 6u ducks left 50 chickens

Case 2,
3 chickens + 2 ducks left 25 chickens
(Made ducks to 6u) by multiply 3u
9u chickens + 6u ducks left 25 chickens

The number of chickens for case 1 and case 2 is same.
Therefore,
4u + 50 = 9u + 25
25 = 5u
1u = 5

a) Total ducks = 6u = 6×5 = 30
b) Total chickens = 4u + 50
= 4×5 + 50
= 70

See 1 Answer

This is duck remain unchanged question.
So we made duck to same unit, 6u

Case 1,
2 chickens + 3 ducks left 50 chickens
(Made duck to 6u) by multiply 2u
4u chickens + 6u ducks left 50 chickens

Case 2,
3 chickens + 2 ducks left 25 chickens
(Made ducks to 6u) by multiply 3u
9u chickens + 6u ducks left 25 chickens

The number of chickens for case 1 and case 2 is same.
Therefore,
4u + 50 = 9u + 25
25 = 5u
1u = 5
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AC Lim
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