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Secondary 1 | Maths
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May i know how to do this question? Its about lowest common multiple and highest common multiples
Date Posted: 2 years ago
Views: 181
What happens if "this certain number" is reduced by 1?
When it is divided by 2...there will be no remainder.
When it is divided by 3, 4, 5 or 6...there will also be no remainder.
This goes to show that if "this certain number" is reduced by 1, the result will be a common multiple of 2, 3, 4, 5 and 6,
The lowest possible of these is 60. All the other possible common multiples will, in fact, be multiples of 60.
[At the secondary level, it is no longer common for you to list down multiples of 2 starting from 2, 4, 6, 8, ... and the same goes for other multiples]
This means that the smallest possible value of "this certain number" must be 60 + 1 = 61.
When it is divided by 2...there will be no remainder.
When it is divided by 3, 4, 5 or 6...there will also be no remainder.
This goes to show that if "this certain number" is reduced by 1, the result will be a common multiple of 2, 3, 4, 5 and 6,
The lowest possible of these is 60. All the other possible common multiples will, in fact, be multiples of 60.
[At the secondary level, it is no longer common for you to list down multiples of 2 starting from 2, 4, 6, 8, ... and the same goes for other multiples]
This means that the smallest possible value of "this certain number" must be 60 + 1 = 61.
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I hope this solution helps you :)
Date Posted:
2 years ago
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