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Question
primary 6 | Maths
2 Answers Below
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aft → A:M = 5u : 6u
b4 → A:M = 5u+18 : 6u
total = M+A → 6u+5u+18 = 84
u = 6
5u+18 = 48 (Ans)
Forwards
LCM (4 , 6) → 12
ate
A → ⅙ = ²⁄₁₂
S → ¼ = ³⁄₁₂
total (at first) → A:S = 12u+42 : 12u
left → A:S = 10u+35 : 9u
A-S = 10u+35 - 9u = u+35 = 45
u = 10
12u+42 = 162 (Ans)
Backwards
LCM (3 , 5) → 15
left
A → 1 - ⅙ = ⅚ = ¹⁵⁄₁₈
S → 1 - ¼ = ¾ = ¹⁵⁄₂₀
total (after) → A:S = 15u+45 : 15u
total (at first) → A:S = 18u+54 : 20u
A-S = 18u+54 - 20u = 54 - 2u = 42
u = 6
18u+54 = 162 (Ans)
See 2 Answers
5u= 5×6=30
5u+18=?