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Secondary 1 | Maths
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Please help me with this question ASAP. Thanks. I really need help
Date Posted: 2 years ago
Views: 188
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Since LCM is 2^3 x 3^2 x 5, the unknown number must have 2^3. Since HCF is 2^2 x 3, the unknown number must have a 3. Hence, we have 2^3 x 3 = 2x2x2x3. Since LCM has 3x3, So the unknown can have max two 3. We have 2x2x2x3x3. Since LCM has 5, the unknow number can have max one 5.
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