Ask Singapore Homework?
Upload a photo of a Singapore homework and someone will email you the solution for free.
Question
secondary 3 | E Maths
One Answer Below
Anyone can contribute an answer, even non-tutors.
It is a math question I dk if it is e maths or a maths
Date Posted: 2 years ago
Views: 438
times 2 at both sides of the equqation
x² + 6x + 2q = 0
x = ( -6 ± √(36-8q) )÷2
= -3 ± √(9-2q)
x₁ = -3 + √(9-2q) = p + √7
x₂ = -3 - √(9-2q)
(a)
p = -3
9-2q = 7 ⇨ q = 1
(b)
x₂ = -3 - √7 ≈ -5.65 (Ans)
x² + 6x + 2q = 0
x = ( -6 ± √(36-8q) )÷2
= -3 ± √(9-2q)
x₁ = -3 + √(9-2q) = p + √7
x₂ = -3 - √(9-2q)
(a)
p = -3
9-2q = 7 ⇨ q = 1
(b)
x₂ = -3 - √7 ≈ -5.65 (Ans)
How did u get p=-3
pls refer to the attached ans
Just do the comparison & match
Just do the comparison & match
https://ask.manytutors.com/questions/119837
See 1 Answer
360 Tutoring Program