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secondary 3 | A Maths
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Solve the simultaneous equation. Please help thank you!
① 4y² = (3x + 1)² = 9x² + 6x + 1
x² - y² = -3
② 4x² - 4y² = -12
① + ② ⇨
4x² = 9x² + 6x + 1 - 12
5x² + 6x - 11 = 0
⇨ (5x + 11) (x - 1) = 0
x₁ = - ¹¹⁄₅ = -2.2
x₂ = 1
⇨ 2y = 3x + 1
y₁ = ( - 3 × ¹¹⁄₅ + 1)÷2 = -2.8
y₂ = (3 × 1 + 1)÷2 = 2
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Eliminate way
Except for the sub method