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secondary 3 | A Maths
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Please help (A math simultaneous equations)
Date Posted: 2 years ago
Views: 526
x/2 = a → x = 2a
y/5 = b → y = 5b
a+b = 5 ①
(1/a)+(1/b) = (a+b)/ab = ⅚
ab = 6 ②
a(5-a) = 6
a² - 5a + 6 = 0
(a - 2)∙(a - 3) = 0
a₁ = 2 → x₁ = 4
a₂ = 3 → x₂ = 6
b₁ = 3 → y₁ = 15
b₂ = 2 → y₂ = 10
Ans
(x₁ , y₁) = (4 , 15)
(x₂ , y₂) = (6 , 10)
y/5 = b → y = 5b
a+b = 5 ①
(1/a)+(1/b) = (a+b)/ab = ⅚
ab = 6 ②
a(5-a) = 6
a² - 5a + 6 = 0
(a - 2)∙(a - 3) = 0
a₁ = 2 → x₁ = 4
a₂ = 3 → x₂ = 6
b₁ = 3 → y₁ = 15
b₂ = 2 → y₂ = 10
Ans
(x₁ , y₁) = (4 , 15)
(x₂ , y₂) = (6 , 10)
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Date Posted:
2 years ago
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