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primary 6 | Maths
| Fractions
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Date Posted: 2 years ago
Views: 361
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Since AB//CD, angle AXZ = angle XZD (alternate angles)
Given in question XZ = YZ, triangle XYZ is an isosceles triangle. Hence to find angle XYZ, take (180 - angle XZY) / 2. (As angle ZXY = angle XYZ)
Given in question XZ = YZ, triangle XYZ is an isosceles triangle. Hence to find angle XYZ, take (180 - angle XZY) / 2. (As angle ZXY = angle XYZ)
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