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Question
primary 5 | Maths
| Fractions
2 Answers Below
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Date Posted: 2 years ago
Views: 576
Farida left ³/5 (3u) after spend 2/5
Farida have total 5u
Maria also left (3u) after spend 18
Therefore, Maria have 3u+18 at 1st.
Total Farida + Maria = 250
5u + 3u + 18 = 250
8u = 232
u = 29
Therefore, Maria at 1st
3u + 18
= (3×29) + 18
= 105.
Farida have total 5u
Maria also left (3u) after spend 18
Therefore, Maria have 3u+18 at 1st.
Total Farida + Maria = 250
5u + 3u + 18 = 250
8u = 232
u = 29
Therefore, Maria at 1st
3u + 18
= (3×29) + 18
= 105.
See 2 Answers
Farida left ³/5 (3u) after spend 2/5
Farida have total 5u
Maria also left (3u) after spend 18
Therefore, Maria have 3u+18 at 1st.
Total Farida + Maria = 250
5u + 3u + 18 = 250
8u = 232
u = 29
Therefore, Maria at 1st
3u + 18
= (3×29) + 18
= 105.
Farida have total 5u
Maria also left (3u) after spend 18
Therefore, Maria have 3u+18 at 1st.
Total Farida + Maria = 250
5u + 3u + 18 = 250
8u = 232
u = 29
Therefore, Maria at 1st
3u + 18
= (3×29) + 18
= 105.
done
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Date Posted:
2 years ago
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