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secondary 3 | A Maths
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care beAr
Care BeAr

secondary 3 chevron_right A Maths chevron_right Singapore

pls help

Date Posted: 2 years ago
Views: 303
Eric Nicholas K
Eric Nicholas K
2 years ago
Something is not right with the question. I attempted to reduce the left side of the equation but could not obtain the right side. I used A = 19 and A = 30 and confirmed that the equation does not hold for each of these two values.

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Arnold K H Tan
Arnold K H Tan's answer
2155 answers (A Helpful Person)
1st
Eric is correct. You let let A = 30⁰ to show the identity is invalid.

You can modify a little, so it can be solved.