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Solving would be standard
Date Posted:
2 years ago
but i alr got that part i meant the angle part
for the angle part, you can refer to your graph/special angles
for sin x = 0, x = 0° or 180° or 360° (by the graph)
for cos x = 1/2, by special angles, x = 60°
however, since cosine is positive in the first and fourth quadrant,
x = 60° or 360°- 60° = 300°
therefore x = 0° or 60° or 180° or 300° or 360°
hope this helps!
for cos x = 1/2, by special angles, x = 60°
however, since cosine is positive in the first and fourth quadrant,
x = 60° or 360°- 60° = 300°
therefore x = 0° or 60° or 180° or 300° or 360°
hope this helps!
thankyou
no problem!
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do clarify if need be
Date Posted:
2 years ago
can u help me with tan x/2 = sin x instead? i understand this qn alr but i can't solve tan x/2 = sin x