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secondary 3 | A Maths
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Date Posted: 2 years ago
Views: 520
a = 1
b = k
c = 2k-5
b² - 4ac
= k² - 4•(2k-5)
= k² - 8k + 20
= ( k - 4 )² + 4 > 0
∴ x² + kx -2k - 5 = 0
has real and distinct roots for all real values of k.
b = k
c = 2k-5
b² - 4ac
= k² - 4•(2k-5)
= k² - 8k + 20
= ( k - 4 )² + 4 > 0
∴ x² + kx -2k - 5 = 0
has real and distinct roots for all real values of k.
See 1 Answer
done
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clear
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Use discriminate to prove.
Date Posted:
2 years ago
ax² + bx + c = 0 , Discriminate = b² - 4ac > 0 ⇾ The quadratic equation has real and distinct roots.
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