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secondary 3 | A Maths
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A math indices
Date Posted: 2 years ago
Views: 222
(i)
0.04 = ¹⁄₂₅ = 5^(-2)
x+2 = -2
x = -4 (Ans)
0.04 = ¹⁄₂₅ = 5^(-2)
x+2 = -2
x = -4 (Ans)
(ii)
LHS
= 3 ^ (2x-1)/2
RHS
= 3 ^ (-2x)
(2x-1)/2 = -2x
2x-1 = -4x
x = ⅙ (Ans)
LHS
= 3 ^ (2x-1)/2
RHS
= 3 ^ (-2x)
(2x-1)/2 = -2x
2x-1 = -4x
x = ⅙ (Ans)
(iii)
LHS
= 2 ^ (3-3x)
RHS
= 2 ^ (2x+2)
3-3x = 2x+2
5x = 1
x = ⅕ (Ans)
LHS
= 2 ^ (3-3x)
RHS
= 2 ^ (2x+2)
3-3x = 2x+2
5x = 1
x = ⅕ (Ans)
(iv)
LHS
= 2 ^ (8x-4) • 2 ^ (3x)
= 2 ^ (11x-4)
RHS
= 2 ^ 18
11x-4= 18
x = 2 (Ans)
LHS
= 2 ^ (8x-4) • 2 ^ (3x)
= 2 ^ (11x-4)
RHS
= 2 ^ 18
11x-4= 18
x = 2 (Ans)
See 2 Answers
done
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clear
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Always simplify such that both side has the same base before comparing the power.
Simplify within bracket first
Simplify within bracket first
Date Posted:
2 years ago
Thank you
Thank you
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