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Secondary 1 | Maths
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hi can anyone help me with this question? i have been stuck on this qn for a long time alr.
Date Posted: 2 years ago
Views: 348
4 possible ans
4×11×208=9152
4×11×218=9592
4×11×213=9372
4×11×223=9812
① AB = 15
② AB = 59
③ AB = 37
④ AB = 81
4×11×208=9152
4×11×218=9592
4×11×213=9372
4×11×223=9812
① AB = 15
② AB = 59
③ AB = 37
④ AB = 81
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Date Posted:
2 years ago
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