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secondary 3 | A Maths
2 Answers Below
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been struggling! help will be greatly appreciated ! <3
Date Posted: 2 years ago
Views: 403
① ↔ ②
5•(x + y) = 4•(x - y - 6)
④ x + 9y = -24
① ↔ ③【y² - x² = (y+x)•(y-x)】
⑤ y - x = 4
④+⑤ → 10y = -20
→ y₁ = -2 ⇨ ⑤ y - x = 4
→ x₁ = -6
④ x + 9y = -24
⑥ x + y = 0
④ - ⑥ → 8y = -24
→ y₂ = -3 ⇨ ④ x + 9y = -24
→ x₂ = 3
5•(x + y) = 4•(x - y - 6)
④ x + 9y = -24
① ↔ ③【y² - x² = (y+x)•(y-x)】
⑤ y - x = 4
④+⑤ → 10y = -20
→ y₁ = -2 ⇨ ⑤ y - x = 4
→ x₁ = -6
④ x + 9y = -24
⑥ x + y = 0
④ - ⑥ → 8y = -24
→ y₂ = -3 ⇨ ④ x + 9y = -24
→ x₂ = 3
See 2 Answers
done
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clear
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look at it as there are 2 simultaneous equations
Date Posted:
2 years ago
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