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secondary 3 | A Maths
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been struggling to solve this equation, can’t seem to get the correct answer. help will be greatly appreciated ! <3
Date Posted: 2 years ago
Views: 504
x-1 = a
y-3 = b
(x-1)² + (y-3)² = 5 ⇨ a² + b² = 5
⇨ b² = 5 - a²
3x = y-5 ⇨ 3(a+1) = b-2 ⇨ 3a+5 = b
⇨ (3a+5)² = b²
(3a+5)² = 5 - a² ⇨ a² + 3a +2 = 0 ⇨ (a+1)⋅(a+2) = 0
a₁ = -1 ⇨ x₁ = 0 ⇨ y₁ = 5
a₂ = -2 ⇨ x₂ = -1 ⇨ y₂ = 2
Pls feel free to ask if any steps stuck you
y-3 = b
(x-1)² + (y-3)² = 5 ⇨ a² + b² = 5
⇨ b² = 5 - a²
3x = y-5 ⇨ 3(a+1) = b-2 ⇨ 3a+5 = b
⇨ (3a+5)² = b²
(3a+5)² = 5 - a² ⇨ a² + 3a +2 = 0 ⇨ (a+1)⋅(a+2) = 0
a₁ = -1 ⇨ x₁ = 0 ⇨ y₁ = 5
a₂ = -2 ⇨ x₂ = -1 ⇨ y₂ = 2
Pls feel free to ask if any steps stuck you
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