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secondary 3 | A Maths
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Pls help to solve q17a
Date Posted: 2 years ago
Views: 173
(a)
9⋅sin(x) = 2⋅sec(x) = 2 / cos(x)
【square at both sides】
81⋅sin²(x) • cos²(x) = 4
sin²(x) ⋅ ( 1-sin²(x) ) = ⁴⁄₈₁
sin²(x) = a
a - a² = ⁴⁄₈₁
a² - a + ⁴⁄₈₁ = 0
1- 4×1×⁴⁄₈₁ = ⁶⁵⁄₈₁
a = (1 ± √ (⁶⁵⁄₈₁) / 2
a₁ = 0.94790320823 = sin²(x) = (±0.97360320882)²
a₂ = 0.05209679176 = sin²(x) = (±0.22824721632)²
x₁ = 76.8061°
x₂ = 256.8061°
x₃ = 13.1939°
x₄ = 193.1939°
9⋅sin(x) = 2⋅sec(x) = 2 / cos(x)
【square at both sides】
81⋅sin²(x) • cos²(x) = 4
sin²(x) ⋅ ( 1-sin²(x) ) = ⁴⁄₈₁
sin²(x) = a
a - a² = ⁴⁄₈₁
a² - a + ⁴⁄₈₁ = 0
1- 4×1×⁴⁄₈₁ = ⁶⁵⁄₈₁
a = (1 ± √ (⁶⁵⁄₈₁) / 2
a₁ = 0.94790320823 = sin²(x) = (±0.97360320882)²
a₂ = 0.05209679176 = sin²(x) = (±0.22824721632)²
x₁ = 76.8061°
x₂ = 256.8061°
x₃ = 13.1939°
x₄ = 193.1939°
Noted thk
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Date Posted:
2 years ago
Noted thk
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