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secondary 3 | A Maths
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Pooh pooh bear
Pooh Pooh Bear

secondary 3 chevron_right A Maths chevron_right Singapore

Pls help to solve q17a

Date Posted: 3 years ago
Views: 214
sstrike
Sstrike
3 years ago
(a)

9⋅sin(x) = 2⋅sec(x) = 2 / cos(x)

【square at both sides】

81⋅sin²(x) • cos²(x) = 4

sin²(x) ⋅ ( 1-sin²(x) ) = ⁴⁄₈₁

sin²(x) = a

a - a² = ⁴⁄₈₁

a² - a + ⁴⁄₈₁ = 0

1- 4×1×⁴⁄₈₁ = ⁶⁵⁄₈₁

a = (1 ± √ (⁶⁵⁄₈₁) / 2

a₁ = 0.94790320823 = sin²(x) = (±0.97360320882)²
a₂ = 0.05209679176 = sin²(x) = (±0.22824721632)²

x₁ = 76.8061°
x₂ = 256.8061°

x₃ = 13.1939°
x₄ = 193.1939°
Pooh pooh bear
Pooh Pooh Bear
3 years ago
Noted thk
sstrike
Sstrike
3 years ago
Welcome

Do you have the answer key together with the working?
Pooh pooh bear
Pooh Pooh Bear
3 years ago
No

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Pooh pooh bear
Pooh Pooh Bear
3 years ago
Noted thk
sstrike
Sstrike
3 years ago
Welcome