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secondary 3 | A Maths
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Need help for 6a , thk
Date Posted: 2 years ago
Views: 549
(a)
sin(2x)
= 2 ⋅ sin(x) ⋅ cos(x) = 3 ⋅ cos(x)
→ cos(x) = 0
x₁ = 90°
x₂ = 270°
sin(2x)
= 2 ⋅ sin(x) ⋅ cos(x) = 3 ⋅ cos(x)
→ cos(x) = 0
x₁ = 90°
x₂ = 270°
Can use tan =sine / cosine
To solve this q
Not sure if they will be looking out for method mark, but I would do this:
sin 2x = 3 cos X
2 sin x cos x - 3 cos x =0
cos x (2 sin x - 3) =0
cos x = 0 or sin x = 3/2 (rej. sin x <1)
the sin part gives the marker the idea that you have considered another possible solution, but rejected as the criteria is not met?
if never put the sin x part or just divide both side by cosine to get tan x I think might - 1 mark
sin 2x = 3 cos X
2 sin x cos x - 3 cos x =0
cos x (2 sin x - 3) =0
cos x = 0 or sin x = 3/2 (rej. sin x <1)
the sin part gives the marker the idea that you have considered another possible solution, but rejected as the criteria is not met?
if never put the sin x part or just divide both side by cosine to get tan x I think might - 1 mark
Noted thk for the clarification
See 1 Answer
done
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Date Posted:
2 years ago
Thank a lot
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