Ask Singapore Homework?
Upload a photo of a Singapore homework and someone will email you the solution for free.
Question
secondary 3 | A Maths
4 Answers Below
Anyone can contribute an answer, even non-tutors.
Help pls
A = 2x
B = 10°
C = 70°
tanC = tan(70°) = 2.74747741945
tanB = tan(10°) = 0.1763269807
cot(2x-10°) = cot(A-B)
= (cotB•cotA + 1)/(cotB - cotA)
= (cosB•cosA + sinB•sinA)
/(cosB•sinA - sinB•cosA)
= (1 + tanB•tanA)
/(tanA - tanB)
= tan(C)
1 + tanB•tanA = tan(C)•(tanA - tanB)
[tan(C)-tan(B)] • tanA
= 1+tan(B)•tan(C)
tanA
= [1+tan(B)•tan(C)] / [tan(C)-tan(B)]
= 1.48445439791 ÷ 2.57115043875
= 0.57735026917
A₁ = 2x = 30°;A₂ = 2x = 210°
x₁ = 15°;x₂ = 195°
x₃ = 105° ;x₄ = 285°
A = ³⁄₂ x
B = 80°
2•cosec(³⁄₂ x - 80°) = -4
⇨
cosec(A - B) = -2
⇨
sin(A - B) = -½
⇨
A-B = asin( -½ ) = 180° + 30° = 210°
OR
A-B = asin( -½ ) = 360° - 30° = 330°
x₁ = (210° + 80°) × ⅔ ≈ 193.33°
x₂ = (330° + 80°) × ⅔ ≈ 273.33°
sec(m) = 1/cos(m)
cosec(m) = 1/sin(m)
sin(40°) = cos(2x+55°)
≈ 0.64278760968
sin(40°) = cos(90°-40°) = cos(2x+55°)
2x+55° = 90°-40° = 50°
OR
2x+55° = 360°-50° = 310°
x₁ = (310° - 55°) ÷ 2 = 127.5°
x₂ = 360° + (50° - 55°) ÷ 2 = 357.5°
-sin(120°)
= sin(180° + 120°) = sin(300°)
= sin(360° - 120°) = sin(240°)
½ x + 70° = 300° → x₁ = 460°
→ 100° ✗
½ x + 70° = 240° → x₂ = 340° ✓
See 4 Answers