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secondary 2 | Maths
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Problem sum
Date Posted: 2 years ago
Views: 306
You will need to form 2 equations.
Let the first digit be x
Let the second digit be y
The expression for the 2-digit number will be 10x+y.
This is because the first digit x is in the tenths place
(Example: to get a 2 digit number 23, you need to take 20 + 3)
From the first sentence of the question:
⅛ (10x + y) = x+y
10x + y = 8x + 8y
2x = 7y —— equation 1
From the second sentence:
10x + y - 45 = 10y + x (same logic as the first number)
9x - 45 = 9y
x - 5 = y —— equation 2
Substituting equation 2 into equation 1:
2x = 7(x - 5)
5x = 35
x = 7
From equation 2,
y = 2
Hence, the original number is
10x + y = 72
Let the first digit be x
Let the second digit be y
The expression for the 2-digit number will be 10x+y.
This is because the first digit x is in the tenths place
(Example: to get a 2 digit number 23, you need to take 20 + 3)
From the first sentence of the question:
⅛ (10x + y) = x+y
10x + y = 8x + 8y
2x = 7y —— equation 1
From the second sentence:
10x + y - 45 = 10y + x (same logic as the first number)
9x - 45 = 9y
x - 5 = y —— equation 2
Substituting equation 2 into equation 1:
2x = 7(x - 5)
5x = 35
x = 7
From equation 2,
y = 2
Hence, the original number is
10x + y = 72
See 2 Answers
done
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clear
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Clue is in the 1/8 where it is a number that is divisible by 8.
Date Posted:
2 years ago
done
{{ upvoteCount }} Upvotes
clear
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Hope this helps
Date Posted:
2 years ago
Thank u for the clear explaination
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