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Question
secondary 3 | E Maths
2 Answers Below
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Date Posted: 3 years ago
Views: 403
numerator coefficient of each
a → 3 + ½ = ⁷⁄₂
b → 6
constant → 8×3
denominator coefficient of each
a → 3+0 = 3
b → 3
constant → 8×1
total
a → ⁷⁄₂ - 3 = ½
b → 6 - 3 = 3
constant → (8×3)÷ (8×1) = 3
Ans: 3 a^ (½) • b³
a → 3 + ½ = ⁷⁄₂
b → 6
constant → 8×3
denominator coefficient of each
a → 3+0 = 3
b → 3
constant → 8×1
total
a → ⁷⁄₂ - 3 = ½
b → 6 - 3 = 3
constant → (8×3)÷ (8×1) = 3
Ans: 3 a^ (½) • b³
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done
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Hope this helps
Date Posted:
3 years ago
done
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Try
Date Posted:
3 years ago
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