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secondary 3 | E Maths
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chapter 1 sec 3
Date Posted: 3 years ago
Views: 235
square root method
(if u cannot remember the eqation)
(x+4) (x-3) = 15
⇨
x² +4x-3x - 12 = 15
⇨
x² + x = 27
⇨
x² + 2•½•x + (½)² = 27 + (½)² = 27.25
⇨【 a² ± 2ab +b² = (a±b)² 】
x → a
½ → b
(x+½)² = 27.25
x₁ = - ½ - √27.25 ≈ -5.72
x₂ = - ½ + √27.25 ≈ 4.72
(if u cannot remember the eqation)
(x+4) (x-3) = 15
⇨
x² +4x-3x - 12 = 15
⇨
x² + x = 27
⇨
x² + 2•½•x + (½)² = 27 + (½)² = 27.25
⇨【 a² ± 2ab +b² = (a±b)² 】
x → a
½ → b
(x+½)² = 27.25
x₁ = - ½ - √27.25 ≈ -5.72
x₂ = - ½ + √27.25 ≈ 4.72
See 2 Answers
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hope this helps
Date Posted:
3 years ago
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Try
Date Posted:
3 years ago
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