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secondary 4 | E Maths
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Jason Lee
Jason Lee

secondary 4 chevron_right E Maths chevron_right Singapore

please help! thanks

Date Posted: 8 months ago
Views: 124
sstrike
Sstrike
8 months ago
Q(3)
cos θ = ⁵⁄₁₃ = b/c
b = 5
c = 13

a² = c² - b²
= 13² - 5²
= 144
= 12²
a = 12

cosec θ = 1/ ( sin θ )
= c/a
= ¹³⁄₁₂ (Ans)

Q(4)
b = k
a = -1
c = √b²+a²
= √k²+1

sec A = 1/ (cos A)
= c/k
= (√k²+1) / k (Ans)

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Johnson
Johnson's answer
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