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## Question

secondary 4 | E Maths

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please help! thanks

cos θ = ⁵⁄₁₃ = b/c

b = 5

c = 13

a² = c² - b²

= 13² - 5²

= 144

= 12²

a = 12

cosec θ = 1/ ( sin θ )

= c/a

= ¹³⁄₁₂ (Ans)

Q(4)

b = k

a = -1

c = √b²+a²

= √k²+1

sec A = 1/ (cos A)

= c/k

= (√k²+1) / k (Ans)

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