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Question
secondary 3 | A Maths
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hello! need help with this qn thank you
Date Posted: 3 years ago
Views: 205
p = 3u
3x² + 12 - px = 0
⇨
x² - ux + 4 = 0
( x - ½u )² = 0
¼u² = 4 ⇨ u² = 16
u = ±4
3u = ±12
p = ±12
3x² + 12 - px = 0
⇨
x² - ux + 4 = 0
( x - ½u )² = 0
¼u² = 4 ⇨ u² = 16
u = ±4
3u = ±12
p = ±12
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Date Posted:
3 years ago
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Date Posted:
3 years ago
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