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Question
secondary 3 | A Maths
2 Answers Below
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hi, pls help me with this qns, tysm!
Date Posted: 3 years ago
Views: 474
1 + log₂ y + 3•log₂ x = 0
1 + log₂ y + log₂ x³ = 0
1 + log₂ (y•x³) = 0
log₂ (y•x³) = -1
y•x³ = ½
y = 1/(2x³) #
1 + log₂ y + log₂ x³ = 0
1 + log₂ (y•x³) = 0
log₂ (y•x³) = -1
y•x³ = ½
y = 1/(2x³) #
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done
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Sorry the previous one was wrong. Thank you to the person who commented! Hopefully this is right? Not great at logs haha
Date Posted:
3 years ago
done
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I think its correct
Date Posted:
3 years ago
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