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junior college 1 | H2 Maths
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junior college 1 chevron_right H2 Maths chevron_right Singapore

Stuck for part iii

Date Posted: 3 years ago
Views: 657
J
J
3 years ago
Setting r = 1 and letting mr + 1 = 3,

m + 1 = 3
m = 2

Setting r = 1 and letting mr + 1 = 4,

m + 1 = 4
m = 3

There are basically two series in there. You'll need to regroup the terms first.


1/1·3 + 1/1·4 + 1/3·5 + 1/4·7 + 1/5·7 + 1/7·10 + ... 1/39·41 + 1/58·61


= 1/1·3 + 1/3·5 + 1/5·7 + ... 1/39·41
+ 1/1·4 + 1/4·7 + 1/7·10 + ... 1/58·61


= 1/(2·1 + 1 - 2)(2·1 +1) + 1/(2·2 + 1 - 2)(2·2 + 1) + 1/(2·3 + 1 - 2)(2·3 + 1) + ... 1/(2·20 + 1 - 2)(2·20 + 1)

+ 1/(3·1 + 1 - 3)(3·1 + 1) + 1/(3·2 + 1 - 3)(3·2 + 1) + 1/(3·3 + 1 - 3)(3·3 + 1) + ... 1/(3·20 + 1 - 3)(3·20 + 1)

□20□□□□ □□ □□□□□□20
= ∑ 1/(2r + 1 - 2)(2r + 1) + ∑ 1/(3r + 1 - 3)(3r + 1)
r=1□□□□□□□□□□□□ r=1


= 20/(2·20 + 1) + 20/(3·20 + 1)

= 20/41 + 20/61

= 2040/2501


The trick is to spot that there is a common difference of 2 for the products in the denominator of the odd terms and common difference of 3 for that of the even terms, from which you can infer that there are two series with different values of m.

Also, 41 = 2·20 + 1 and 60 = 3·20 + 1 follows the mr + 1 and tells you that each series ends at 20 terms (i.e n = 20)
Eric Nicholas K
Eric Nicholas K
3 years ago
Wow, you actually used boxes to give the spacing.

Unfortunately, on my phone, it appears that the second 20 is placed some distance to the right of where it should be. I guess it’s just different phones and different computer screens.
J
J
3 years ago
Been doing so for a while now. The app doesn't allow multiple blank spaces (they will still appear bunched up)

The best alternative was these white square boxes.

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