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secondary 3 | A Maths
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Need help with (a). Thank You
Date Posted: 3 years ago
Views: 204
You should continue from your working :
3√3 / 2 cos x - 11/2 sin x = 0
3√3 / 2 cos x = 11/2 sin x
sin x / cos x = 3√3 / 2 ÷ 11/2
tan x = 3√3 / 11
basic angle = tan-¹ 3√3 / 11 ≈ 25.28° (2 d.p)
Since tan x is positive, we look at the 1st and 3rd quadrant.
x ≈ 25.28°, 180° + 25.28°
x ≈ 25.28°, 205.28°
x = 25.3° , 205.3° (1 d.p)
3√3 / 2 cos x - 11/2 sin x = 0
3√3 / 2 cos x = 11/2 sin x
sin x / cos x = 3√3 / 2 ÷ 11/2
tan x = 3√3 / 11
basic angle = tan-¹ 3√3 / 11 ≈ 25.28° (2 d.p)
Since tan x is positive, we look at the 1st and 3rd quadrant.
x ≈ 25.28°, 180° + 25.28°
x ≈ 25.28°, 205.28°
x = 25.3° , 205.3° (1 d.p)
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Date Posted:
3 years ago
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