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secondary 3 | A Maths

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Need help with (a). Thank You

3√3 / 2 cos x - 11/2 sin x = 0

3√3 / 2 cos x = 11/2 sin x

sin x / cos x = 3√3 / 2 ÷ 11/2

tan x = 3√3 / 11

basic angle = tan-¹ 3√3 / 11 ≈ 25.28° (2 d.p)

Since tan x is positive, we look at the 1st and 3rd quadrant.

x ≈ 25.28°, 180° + 25.28°

x ≈ 25.28°, 205.28°

x = 25.3° , 205.3° (1 d.p)

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