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secondary 3 | E Maths
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Thea
Thea

secondary 3 chevron_right E Maths chevron_right Singapore

Can someone help me with part d

Date Posted: 2 years ago
Views: 144
J
J
2 years ago
∠BAD = ∠BDA = 65°
(base angles of isosceles ∆, since AB = BD)

∠BCD + ∠BAD = 180°
(opposite angles of a cyclic quadrilateral add up to 180°)
Or
(angles in opposite segments are supplementary)


∠BCD = 180° - 65° = 115°

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AC Lim
Ac Lim's answer
12074 answers (A Helpful Person)
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Hope this helps
AC Lim
AC Lim
2 years ago
Sorry, i found angle ACD... please add back 65.. answer 115°
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AC Lim
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12074 answers (A Helpful Person)
Hope this helps