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secondary 3 | A Maths
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Date Posted: 3 years ago
Views: 174
(x+B)•(x+1)
= x² + (B+1)x + B
m = B+1
(Ax-1)•(x² + mx + B)
= Ax³ + Amx² + ABx
- x² - mx - B
x³ →
【A = 2】
x² → Am-1 = A(B+1)-1 = 2B+1 = -5
【B = -3】
x → AB-m = -6+2 = -4 ✔ ✔ ✔
C-B → C+3 = 8
【C = 5】
= x² + (B+1)x + B
m = B+1
(Ax-1)•(x² + mx + B)
= Ax³ + Amx² + ABx
- x² - mx - B
x³ →
【A = 2】
x² → Am-1 = A(B+1)-1 = 2B+1 = -5
【B = -3】
x → AB-m = -6+2 = -4 ✔ ✔ ✔
C-B → C+3 = 8
【C = 5】
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