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Yih
Yih

Secondary 3 chevron_right A Maths chevron_right Malaysia

Please help to solve it. Thank you

Date Posted: 3 years ago
Views: 668
J
J
3 years ago
Let x = √(4 + √15) + √(4 - √15)

x² = [√(4 + √15) + √(4 - √15)]²

x² = (√(4 + √15))² + 2 √(4 + √15) √(4 - √15) + (√(4 - √15))²

x² = 4 + √15 + 2√[(4+√15)(4-√15)] + 4 - √15

x² = 8 + 2√(4² - (√15)²)

x² = 8 + 2√(16 - 15)

x² = 8 + 2√1

x² = 8 + 2

x² = 10

x = √10 or x = -√10 (rejected as x is the product of two positive square roots and so x cannot be negative)

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Eric Nicholas K
Eric Nicholas K's answer
5997 answers (Tutor Details)
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Rough idea
J
J
3 years ago
Missing the square root symbol for (√(4 - √15))²
Eric Nicholas K
Eric Nicholas K
3 years ago
Wow, this is what happens when there are too many square roots in an expression.

Maybe putting it in indices format would reduce the occurrence of careless mistakes .
J
J
3 years ago
Two √ still okay.

Three, four, five, etc, will be hard to keep track.

Brackets too. That's why I prefer to use some [ ] sometimes instead of many ( )
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sstrike
Sstrike's answer
5558 answers (A Helpful Person)