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primary 5 | Maths
| Fractions
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Date Posted: 2 years ago
Views: 142
remainder → 1 - ³⁄₇ = ⁴⁄₇
O → ⁵⁄₁₂ × ⁴⁄₇ = ⁵⁄₂₁
N → ³⁄₇ = ⁹⁄₂₁
(a)
N+O = ⁹⁄₂₁ + ⁵⁄₂₁ = ⅔ (Ans)
(b)
⅔ = ¹²⁶⁄₁₈₉
126 ÷ ⅔ = 189 (Ans)
O → ⁵⁄₁₂ × ⁴⁄₇ = ⁵⁄₂₁
N → ³⁄₇ = ⁹⁄₂₁
(a)
N+O = ⁹⁄₂₁ + ⁵⁄₂₁ = ⅔ (Ans)
(b)
⅔ = ¹²⁶⁄₁₈₉
126 ÷ ⅔ = 189 (Ans)
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Date Posted:
2 years ago
Thx
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